Super Silver Haze
02-23-2008, 01:28 PM
http://xs124.xs.to/xs124/08086/103-catan118.jpg
I’m playing a game of Settlers of Catan against some friends, and I’ve just completed my turn. While I’m one point away from winning, my opponents are also near the 10 Victory Points they need to win. I’ve emptied my hand of all resources, save a solitary Sheep, in order to seize Longest Road, whereas my opponents have full hands. It’s not looking good. But I see a way to win, despite my lousy dice rolling!
I’ve been paying attention, and know exactly what resources my opponents have. In addition, I accidentally bumped the table, so we all know that the first three cards in the development card stack are Knight, Victory Point, Knight. My opponents, in turn order, are as follows:
Pink (4 Cities, for 8 VP): Has 1 Clay, 3 Wood, 1 Ore.
Blue (4 Cities, 1 VP card revealed, for 9 VP): Has 2 Clay, 2 Wood, 1 Sheep, 1 Grain.
Yellow (3 Cities, Largest Army, 3 Knight cards revealed, 1 VP card revealed, for 9 VP): Has 2 Ore, 2 Grain.
And me:
Green (2 Cities, 3 Settlements, Longest Road, for 9 VP): Has 1 Sheep
Your solution is the letter "t", followed by the required rolls over the next three turns for me to be able to win the game on my next turn, no matter what I roll on my turn, along with the number of wood, clay, sheep, grain, and ore I will have at the start of my turn. Use two digits for each die roll, and one digit for each resource count; if the winning rolls were 8, 10, and 2, and I had one wood, one clay, two sheep, and one grain, your answer would be t08100211210.
Concise rules of Settlers of Catan:
Each player builds roads, settlements, and cities, buys development cards, and tries to reach 10 Victory Points. Each turn, the active player rolls the dice, and hexes with the number rolled produce one of that resource for each Settlement, two for each City, adjacent to that hex. For example, if an 11 is rolled, Yellow produces two Wood off the 11 wood, and Yellow and Pink produce 2 Ore off the 11 ore. The active player may then trade with other players, or with the bank (4 of one resource for 1 of any resource). If the player has a Settlement or City on a 3:1 port (edge position connected to a 3:1 circle), he may instead trade 3 of one resource for 1 of another. If a player has a Settlement or City on a resource port (the Pink player is on the Clay port, as indicated by the red circle), he may trade 2 of that resource for 1 of another.
If a 7 is rolled, no resources are produced. Anyone with 8 or more resource cards must discard half, rounded down. The Robber (gray pawn, currently on the 6 sheep) is moved to another hex, and steals a resource from a player with a Settlement or City adjacent to that hex. No resources are produced from the tile where the Robber rests.
Note: We are playing no trade, reverse robber. We may not trade with other players. If the robber is to be moved, we must put it on a hex that only we border, or any hex we border if that is not possible.
The resources are Wood (brown), Clay (red), Sheep (green), Grain (yellow), and Ore (gray).
· 1 Wood, 1 Clay buys a Road. Roads are built along hex edges off of other roads, settlements, or cities. A player who builds the longest road (at least 5 segments) gets 2 VP.
· 1 Wood, 1 Clay, 1 Sheep, 1 Grain buys a Settlement, worth 1 VP. Settlements are built at vertices, adjacent to roads, and must be at least two edges away from all other settlements or cities. For example, the 6 sheep-3 clay-ore port is not a legal placement for a Green settlement, but the 3 clay-ocean-ore port and the 8 sheep-3 clay-ocean intersections are legal.
· 1 Sheep, 1 Grain, 1 Ore buys a Development Card. They are either Knight, Year of Plenty, Monopoly, Road Building, or cards worth 1 Victory Point. A player who plays the most Knight cards (at least 3) gets 2 VP for Largest Army. [Since only the Victory Point cards can be played the turn drawn, they are the only ones relevant to this puzzle.]
· 2 Grain, 3 Ore upgrades a Settlement to a City, worth 2 VP.
Link to next puzzle (http://www.actuarialoutpost.com/actuarial_discussion_forum/showthread.php?p=2688804)
I’m playing a game of Settlers of Catan against some friends, and I’ve just completed my turn. While I’m one point away from winning, my opponents are also near the 10 Victory Points they need to win. I’ve emptied my hand of all resources, save a solitary Sheep, in order to seize Longest Road, whereas my opponents have full hands. It’s not looking good. But I see a way to win, despite my lousy dice rolling!
I’ve been paying attention, and know exactly what resources my opponents have. In addition, I accidentally bumped the table, so we all know that the first three cards in the development card stack are Knight, Victory Point, Knight. My opponents, in turn order, are as follows:
Pink (4 Cities, for 8 VP): Has 1 Clay, 3 Wood, 1 Ore.
Blue (4 Cities, 1 VP card revealed, for 9 VP): Has 2 Clay, 2 Wood, 1 Sheep, 1 Grain.
Yellow (3 Cities, Largest Army, 3 Knight cards revealed, 1 VP card revealed, for 9 VP): Has 2 Ore, 2 Grain.
And me:
Green (2 Cities, 3 Settlements, Longest Road, for 9 VP): Has 1 Sheep
Your solution is the letter "t", followed by the required rolls over the next three turns for me to be able to win the game on my next turn, no matter what I roll on my turn, along with the number of wood, clay, sheep, grain, and ore I will have at the start of my turn. Use two digits for each die roll, and one digit for each resource count; if the winning rolls were 8, 10, and 2, and I had one wood, one clay, two sheep, and one grain, your answer would be t08100211210.
Concise rules of Settlers of Catan:
Each player builds roads, settlements, and cities, buys development cards, and tries to reach 10 Victory Points. Each turn, the active player rolls the dice, and hexes with the number rolled produce one of that resource for each Settlement, two for each City, adjacent to that hex. For example, if an 11 is rolled, Yellow produces two Wood off the 11 wood, and Yellow and Pink produce 2 Ore off the 11 ore. The active player may then trade with other players, or with the bank (4 of one resource for 1 of any resource). If the player has a Settlement or City on a 3:1 port (edge position connected to a 3:1 circle), he may instead trade 3 of one resource for 1 of another. If a player has a Settlement or City on a resource port (the Pink player is on the Clay port, as indicated by the red circle), he may trade 2 of that resource for 1 of another.
If a 7 is rolled, no resources are produced. Anyone with 8 or more resource cards must discard half, rounded down. The Robber (gray pawn, currently on the 6 sheep) is moved to another hex, and steals a resource from a player with a Settlement or City adjacent to that hex. No resources are produced from the tile where the Robber rests.
Note: We are playing no trade, reverse robber. We may not trade with other players. If the robber is to be moved, we must put it on a hex that only we border, or any hex we border if that is not possible.
The resources are Wood (brown), Clay (red), Sheep (green), Grain (yellow), and Ore (gray).
· 1 Wood, 1 Clay buys a Road. Roads are built along hex edges off of other roads, settlements, or cities. A player who builds the longest road (at least 5 segments) gets 2 VP.
· 1 Wood, 1 Clay, 1 Sheep, 1 Grain buys a Settlement, worth 1 VP. Settlements are built at vertices, adjacent to roads, and must be at least two edges away from all other settlements or cities. For example, the 6 sheep-3 clay-ore port is not a legal placement for a Green settlement, but the 3 clay-ocean-ore port and the 8 sheep-3 clay-ocean intersections are legal.
· 1 Sheep, 1 Grain, 1 Ore buys a Development Card. They are either Knight, Year of Plenty, Monopoly, Road Building, or cards worth 1 Victory Point. A player who plays the most Knight cards (at least 3) gets 2 VP for Largest Army. [Since only the Victory Point cards can be played the turn drawn, they are the only ones relevant to this puzzle.]
· 2 Grain, 3 Ore upgrades a Settlement to a City, worth 2 VP.
Link to next puzzle (http://www.actuarialoutpost.com/actuarial_discussion_forum/showthread.php?p=2688804)