VHM and EVPV

[enaj]

Can anyone tell me what the VHM and EVPV are equivalent to? I know the formulas are:

EVPV = E[Var(X|Y)]
VHM = Var[E(X|Y)]

In 2001 #30, it appears that

EVPV = E[Var(X / Y) * Y^2]
VHM = Var[E(X / Y)*Y]


I'm not sure how these two forms are equal. I'd appreciate anyone's input on this.

[DOT]

Can anyone tell me what the VHM and EVPV are equivalent to? I know the formulas are:

EVPV = E[Var(X|Y)]
VHM = Var[E(X|Y)]

In 2001 #30, it appears that

EVPV = E[Var(X / Y) * Y^2]
VHM = Var[E(X / Y)*Y]


I'm not sure how these two forms are equal. I'd appreciate anyone's input on this.

EVPV = E[Var(X|Y)] = E[Var(d*Y|Y)] = E[(Y^2)]*Var(d) = {E[Y^2] + E[Y]^2}*Var(d)

VHM = Var[E(X|Y)] = Var[E(dY|Y)] = (d^2)*Var(Y)

d = X/Y

[Five in Two]

I'm guessing you never took exam 4/C?

[intelmic]

I was *the king* at VHM, EPV when I took C. But it seems like such a long time ago... I even struggled when I first read Brosius.

[SoCalChavo]

EVPV = E[Var(X|Y)] = E[Var(d*Y|Y)] = E[(Y^2)]*Var(d) = {E[Y^2] + E[Y]^2}*Var(d)

VHM = Var[E(X|Y)] = Var[E(dY|Y)] = (d^2)*Var(Y)

d = X/Y


The formula for the EVPV should finish as:
{VAR[Y] + E[Y]^2}*Var(d) not {E[Y^2] + E[Y]^2}*Var(d)

[DOT]

The formula for the EVPV should finish as:
{VAR[Y] + E[Y]^2}*Var(d) not {E[Y^2] + E[Y]^2}*Var(d)

Right. Sorry about that.