Agtuary
10-27-2002, 02:59 PM
I was attempting a problem where the expected number of items was either 7, 8, 9 or 10, with equal likelihood. The solution determined the Var(N) using E(N^2) - E(N)^2 = 73.5 - 8.5^2 = 1.25.
I am probably missing something very basic but why is this different than a uniform distribution from [7,10] with Var(N) = (10-7)^2/12 = 0.75?
I am probably missing something very basic but why is this different than a uniform distribution from [7,10] with Var(N) = (10-7)^2/12 = 0.75?