Maitre_Absolut
09-28-2006, 07:34 PM
For the iterative formula for Xi
Felblum's article has the weight's squared on the numerator and denominator
CSM has the weight squared on the denominator only. (probably a typo)
All 10 has no squares on either weights.
Feldblum's formula assumes SSE = SS (NijRij - NijXiYj)^2
All 10's assumes SSE = SS Nij (Rij - XiYj)^2
Naturally i would trust the articles forumla (Felblums), but Q #1 1994 has All10's formula as the answer, with reference to Brown.
So i guess Brown used All 10's version of the SSE, and Feldblum has updated that formula in his article?
EDIT: i just read the Errata....ok for the Mult Least Squares, but now the X squared SSE formulas have the weight inside the square....why hasnt he corrected this formula?
Felblum's article has the weight's squared on the numerator and denominator
CSM has the weight squared on the denominator only. (probably a typo)
All 10 has no squares on either weights.
Feldblum's formula assumes SSE = SS (NijRij - NijXiYj)^2
All 10's assumes SSE = SS Nij (Rij - XiYj)^2
Naturally i would trust the articles forumla (Felblums), but Q #1 1994 has All10's formula as the answer, with reference to Brown.
So i guess Brown used All 10's version of the SSE, and Feldblum has updated that formula in his article?
EDIT: i just read the Errata....ok for the Mult Least Squares, but now the X squared SSE formulas have the weight inside the square....why hasnt he corrected this formula?