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Search: Posts Made By: RobertR1990
Forum: Probability 09-17-2016, 09:19 PM
Replies: 39
Views: 80,059
Posted By RobertR1990
Smile TIA Practice Exam 3 #24

Hello I think I am misunderstanding how to organize the payment structure for this problem. I hope someone could help me out.
N= # of Losses ~Poisson(lamda=2.5)
Y= Payment
Goal : E(Y)
I...
Forum: Probability 09-15-2016, 12:24 PM
Replies: 39
Views: 80,059
Posted By RobertR1990
Thumbs up TIA Practice Exam 2

Yes it does MathDoctorG thank you very much.
Forum: Probability 09-15-2016, 11:27 AM
Replies: 39
Views: 80,059
Posted By RobertR1990
Smile TIA Practice Exam 2 Questions

Hello. I am wondering if someone could help me out with a few problems such as #4 and #21, #25 respectively on TIA practice exam 2.

Q1: For #4 Why is g(x) monotone for f(x)= 2/(pi(1+4x^2))?
To...
Forum: Probability 07-29-2016, 04:48 PM
Replies: 1
Views: 698
Posted By RobertR1990
Smile ASM Exam 2 #8

I am wondering if there is another way to find the expected value rather than using tabular integration or integration by parts twice.
Here is the problem: A device contains two circuits. The second...
Forum: Probability 07-29-2016, 02:19 PM
Replies: 1
Views: 573
Posted By RobertR1990
Smile SOA 96

Hello I understand the sample solution but, I am trying to figure out the answer using Bernoulli and I am wondering if this approach is valid? This is what I have:
X = Cost ~ Bernoulli
Goal:...
Forum: Short-Term Actuarial Math 11-26-2015, 08:00 PM
Replies: 3
Views: 582
Posted By RobertR1990
Thank you same to you also.

Thank you same to you also.
Forum: Probability 09-25-2015, 11:55 PM
Replies: 3
Views: 569
Posted By RobertR1990
Thank you. I think I can see the trick now.

Thank you. I think I can see the trick now.
Forum: Probability 09-25-2015, 04:29 PM
Replies: 3
Views: 569
Posted By RobertR1990
Question ASM Exam 9 #20

Let N1 and N2 be two independent Poisson random variables with expected values E(N1)=2 and E(N2)= 3. Find V(N1|N1+N2 = 5).
Answer : C 1.2.
The issue I am having has to do with simplifying...
Forum: Probability 09-19-2015, 06:04 PM
Replies: 4
Views: 500
Posted By RobertR1990
Thank you.

Thank you.
Forum: Probability 09-19-2015, 06:01 PM
Replies: 4
Views: 751
Posted By RobertR1990
OK. I will take your advice on Q1 and Q2. I guess...

OK. I will take your advice on Q1 and Q2. I guess I need to study those concepts further. For Q3 I think determining the joint density for X1 and Xn I am struggling with the most. Thank you for your...
Forum: Probability 09-19-2015, 05:53 PM
Replies: 4
Views: 500
Posted By RobertR1990
OK. So this is the same method as using u...

OK. So this is the same method as using u substitution?
Forum: Probability 09-18-2015, 07:59 PM
Replies: 4
Views: 751
Posted By RobertR1990
Question ASM Exam 6 # 21

Let X1,X2,X3,.....,Xn be the order statistics from the uniform distribution on [0,1]. Find the correlation coefficient of X1 and Xn.
Answer: 1/n
Solution:
If X is uniform on [0,1] so is 1-X. ...
Forum: Probability 09-18-2015, 06:49 PM
Replies: 4
Views: 500
Posted By RobertR1990
Question ASM Exam 6 # 18

You are given that the hazard rate for a random variable X is lamda(x) = 1/2(x)^-1/2 for x > 0 and 0 otherwise. Find the mean of X.
Solution:
We calculate the survival function of X as e ^(-...
Forum: Probability 09-16-2015, 12:03 AM
Replies: 7
Views: 966
Posted By RobertR1990
Smile Thank you it is much clearer now.

Thank you it is much clearer now.
Forum: Probability 09-15-2015, 06:50 PM
Replies: 7
Views: 966
Posted By RobertR1990
Question ASM exam 6 #11

Let X1, X2, X3, ...., X8 be order statistics from a random sample X1, X2, X3, ...X8 of size 8 from a continuous probability distribution. What is the probability that the median of the distribution...
Forum: Probability 09-15-2015, 06:12 PM
Replies: 4
Views: 593
Posted By RobertR1990
Smile Thank you. It makes sense.

Thank you. It makes sense.
Forum: Probability 09-11-2015, 03:08 AM
Replies: 2
Views: 449
Posted By RobertR1990
Smile Thank you. My problem was I did not know the...

Thank you. My problem was I did not know the definition of covariance in words. Makes sense now.
Forum: Probability 09-10-2015, 05:21 PM
Replies: 2
Views: 449
Posted By RobertR1990
Question ASM Exam 4 #5

See below for histogram and answer choices. The correct answer is E. I understand the first part where V(X)<V(Y) but not V(X+Y) <V(X) + V(Y).
Q: How do we know the Cov(X,Y) is negative?
If there...
Forum: Probability 09-09-2015, 05:45 PM
Replies: 2
Views: 1,327
Posted By RobertR1990
Thank you. This makes a lot of sense.

Thank you. This makes a lot of sense.
Forum: Probability 09-09-2015, 04:24 PM
Replies: 4
Views: 593
Posted By RobertR1990
Answer: 66.7

Answer: 66.7
Forum: Probability 09-09-2015, 04:22 PM
Replies: 0
Views: 560
Posted By RobertR1990
Question ASM Exam 3 #27

Defective items on an assembly line occur independently with probability of .05. A random sample of 100 items is taken. What is the probability that the first item sampled is not defective, given...
Forum: Probability 09-09-2015, 01:13 PM
Replies: 2
Views: 1,327
Posted By RobertR1990
Smile ASM Exam 3 #11

An insurance contract reimburses a family's automobile accident losses up to a maximum of two accidents per year. The joint probability distribution for the # of accidents of a three person family...
Forum: Probability 09-09-2015, 12:09 PM
Replies: 4
Views: 593
Posted By RobertR1990
Cool ASM Practice Exam 3 #10 clarification

Suppose the remaining lifetimes of a husband and a wife are independent and uniformly distributed on the interval (0,40). An insurance company offers two products to married couples:
1) One which...
Forum: Fantasy Football Sub-Forum 09-04-2015, 07:23 PM
Replies: 169
Views: 7,439
Posted By RobertR1990
16.07 Fred Jackson RB

16.07 Fred Jackson RB
Forum: Probability 09-04-2015, 07:18 PM
Replies: 1
Views: 1,182
Posted By RobertR1990
Question SOA 172

A policyholder has probability 0.7 of having no claims, 0.2 of having exactly one claim,
and 0.1 of having exactly two claims. Claim amounts are uniformly distributed on the
interval [0, 60] and...
Showing results 1 to 25 of 54

 

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