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Old 11-16-2015, 06:49 PM
tvossler tvossler is offline
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Default Conditional Probability

In general if P(A)>0, then P(B|A) = P(A and B)/P(A).

Sometimes, as in the case of SOA #17 from November 2001: The loss due to a fire in a commercial building is modeled by a random variable X with density function f(x) =.005(20-x) for 0<x<20

Given that a fire loss exceeds 8, what is the probability that it exceeds 16?

That conditional probability is shortened to P(B|A) =P(AandB)/P(A) = P(B)/P(A).

What is this due to? Why does it sometimes get reduced to this and other times not?

Thank you.
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