I found the easiest way for me to solve it was replacing x=1/2 right away, then the integral for all values of y is just the difference of 2 easy ones. I used the basic result of an Erlang that gives
(integral from 0 to infinite) (x^a * e^(x/b) dx) = a! * b^(a+1)
Afterthought one year later: It's much simpler if the survival function is used: Pr(t>1/2) and at the end finding the complement. And when realizing that the integral Y*eY^dY is the expected value of an exponential with mean = 1.
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Last edited by gauchodelpaso; 09102019 at 12:24 PM..
