Help plz! Given pdf to estimate prob. of small interval
From an online study material, an example question under AgeAtDeath RV.
An ageatdeath random variable is modeled by an exponential random variable
with PDF f(x) = 0.34e^0.34x; x >= 0. Use the given PDF to estimate
Pr(1 < X < 1:02).
The answer is just one line:
Pr(1 < X < 1.02) 0.02*f(1) = 0.005
Could anyone tell me how this is derived???
Thanks!
BTW it's interesting that exam MLC has been revised for several times, from pencil & paper MC to almost CBT, and now it contains both MC and WA.
