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#1
11-02-2005, 11:08 AM
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Gambling at the Horse Track
OK,
I got the answer that I believe is either right or too obvious and wrong, it was 13/60. That is just adding out of 60 attempts, there were 2*3 plus 1*7... Someone please agree here? I am not so worried b/c I figured to do poorly on Stats but getting this one right helps. 
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#3
11-02-2005, 11:17 AM
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It did seem too obvious, but I got the same answer and here's why.
I looked at it as a method of moments of a binomial with M fixed at 60. So the expected amount correct would be M*p = X and we knew both X and M. p = X/M = 13/60. Let me know if that makes sense.
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#7
11-02-2005, 11:48 AM
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I concur, A. 13/60
__________________
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