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#1
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Dear All
In this question I cant figure out why choices d and e are false . In the answer it just mention b is ture . I have no idea to determine formulas although I have check some of text books . Whould someone can help me ?Thanks . Have a nice weekend |
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#2
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Utilize the complements. You should know that A u B|C = A|C + B|C - A n B|C. Therefore, A' u B'|C = A'|C + B'|C - A' n B'|C. Plug in the information given and see which statements are true. Hope this helps!
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#3
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Thanks for repling
I know this complement and get the answer is b . I am courious what concepts being lose that I cant get why the d and e are false . Someone tell me I should apply P(a union b l c)+P(a union b l c")=P(a union b) and this formula can explain why d is false . Because I never see the formula at text books I examine it by venn diagram it seem to be have problems . |
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#4
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what are the numbers in the problem? Numbers are to blurry when I try to enlarge.
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#5
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I can't read the OP that well, but it looks like it is an old exam 110 problem from 1990, which says (I apologize for formatting problems, I'm copying and pasting from a PDF):
Let A, B, and C be events such that P[A | C] = 0.05 and P[B | C] = 0.05. Which of the following statements must be true? A. P[AB | C] = 0.05^2 B. P[A′B′ | C] ≥ 0.90 C. P[A ∪ B | C] ≤ 0.05 D. P[A′ ∪ B′ | C] ≥ 1 − (0.05)^2 E. P[A ∪ B | C] ≥ 0.10 There are two points in the problem. One is that the probabilities conditioned on C are still probabilities, so our usual rules of probability still hold. Then given that, the inequalities in C and E are reversed, making those false, and the statements for A and D require writing P[AB] as P[A]*P[b] or P[A' B'] as P[A']*P[B'], both of which require independence which need not hold making those statements false as well. Last edited by daaaave; 02-10-2012 at 10:27 PM.. |
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#6
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Thanks for repling
The OP have some different in choices D and E The D. P[A ∪ B | C^'] ≥ 1 − (0.05)^2 E. P[A ∪ B | C^'] ≥ 0.10 How can I get the P( A l C' ) and P( B l C' ) ? Last edited by alenblue; 02-12-2012 at 10:58 PM.. |
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