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Probability Old Exam P Forum 

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#21




I believe the solution interprets the wording to mean:
The family car will be driven some known distance per year, e.g. 40,000 km. (For an alternative distance, everything changes proportionately.) The mother will drive 20,000 km; the father will drive 16,000; the son will drive 4,000. If the mother were to drive all 40,000 and the others 0, or the father to drive all 40,000 and the others 0, the probability of an accident is 1%. If the son were to drive all 40,000 and the others 0, the probability of an accident is 5%. That's a reasonable interpretation, but the words could also mean: If the mother were to drive her 20,000 and the others 0, or the father to drive his 16,000 and the others 0, the probability of an accident is 1%. If the son were to drive his 4,000 and the others 0, the probability of an accident is 5%. Edited to add: the intended meaning is probably the better choice, since the alternative could be stated much more simply as "the probability that the mother in the year is in an accident is 1%; that the father is, is 1%; that the son is, is 5%" Last edited by Gandalf; 04032006 at 10:23 AM.. 
#22




I agree that the wording makes the problem somewhat
ambiguous. I will try to clean up the wording to make it more clear. Sam Broverman 
#23




Aprl 10 Question
You can find the question at:
http://www.sambroverman.com/apr10p.pdf Sam Broverman 2brove@rogers.com 
#24




April 17 Question
You can find the question at:
http://www.sambroverman.com/apr17p.pdf A corrected solution has been posted, April 21, 2006. Sam Broverman 2brove@rogers.com Last edited by sam_broverman; 04212006 at 05:44 PM.. 
#25




Re: Apr 17th problem
Hello,
The question says there is a max of 8 on the payment the insurer will pay, however the solution states the insurer will pay 10 if X+Y> 10. I was wondering if I was misreading this? 
#26




Thanks for pointing that out. The solution should have a maximum
payment of 8, not 10, so the integral with the max payment of 10 should have a max of 8. I'll post a correction shortly. Sam Broverman 
#27




April 24 Question
You can find the question at:
http://www.sambroverman.com/apr24p.pdf Sam Broverman 2brove@rogers.com 
#28




May 1 Question

#29




Hi
Would you think that something as convoluted as this would come up on the exam, or is this an example of an extended problem to help extend the material http://www.sambroverman.com/dec26p.pdf Cheers, 
#30




Mallkins,
It is quite convoluted, and I wouldn't expect a question like this one on the exam. It really is a stretch for the Exam P material. I must have been in a bad mood when I made it up (or hungover, it was Boxing Day after all) . Sam Broverman 
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