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#1




SOA #304
Hello!
Can someone please explain to me how we know that the sum of the alphas add to 1? Thank you. I'm having trouble posting an image of the problem, so sorry.
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#2




In the limit as y goes to infinity, all the cdfs go to one.

#3




Quote:
Yes, I understand that the cdfs sum to 1. What confuses me is that the density function associated with each alpha is different, ie, each exponential density has a different theta. I can see how the alphas would sum to 1 if the density function associated with each alpha used the same theta but they don't.??
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#4




The cdfs don't sum to 1. The cdfs weighted by the alphas sum to 1. If the alphas didn't sum to 1 then the cdf of the mixed distribution would not be 1 in the limit.

#5




Quote:
Right. Still confused. Say that: alpha 1 = .1 alpha 2 = .2 alpha 3 = .3 alpha 4 = .4 Each one of these alphas are being multiplied by a different density function (i.e. and exponential with different thetas). How does the fact that the alphas sum to one ensure that the cdf will be one? I'm so confused.
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#6




Quote:

#7




Y is a mixture of 4 different distributions, namely exponentials with means theta_1, theta_2, theta_3, and theta_4 respectively. The alpha_i are probabilities of selecting each of those 4 different components of the mixture, and as such sum to 1 because the sum of the probabilities is 1.

#8




Hello and thank you for all the responses. They've all been very helpful and I think I have a much better understanding of this problem. Your explanations all make sense.
I hope that I can quickly assimilate this type of problem should it come up on an exam. Again, thank you all.
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