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#1




FM Question of Unknown Time
A deposits 10 today and 30 in 5 years at a simple interest rate of 11% per year. B makes the same deposits but at times n and 2n, at an annual effective rate of 9.15%. At 10 years A and B's accumulated values are equal. Calculate n.
I set up an equation of value comparing at time 10 as follows: 10(1+.11(10))+30(1+.11(5))=10(1.0915)^(10n)+30(1.0915)^(102n) and got it to here: 2.8123=(1.0915)^(n)+3(1.0915)^(2n) but at this point it seems algebraically unsolvable? There's no log properties that will isolate n, so how can I solve this? 
#2




Let x = 1.0915^n
You'll get a quadratic in x. Find its roots. You take it from there.
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