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#31




July 16th problem
Good hard problem.
Couldn't you treat this as a simple binomial distribution. n =7 p = Pr( of picking your own coat/hat) = 1/n = 1/7 E(X) = n x p = n x 1/n = 1. 
#32




Binomial distribution?
Each subsequent Bernoulli Trial is independent of the previous one in the binomial distribution. Here, if you pick a coat, that coat is no longer available for the next person to pick, so there is no independence.
Yours, Krzys' Ostaszewski Quote:

#34




July 30, 2005 exercise
It is posted at:
http://www.math.ilstu.edu/krzysio/7...OExercise.pdf This will show that the problem described here cannot be modeled with the binomial distribution. Yours, Krzys' Last edited by krzysio; 07272005 at 11:03 AM.. 
#35




August 6, 2005, exercise
Please find it at:
http://www.math.ilstu.edu/krzysio/865KOExercise.pdf I hope you will enjoy it. Yours, Krzys' Ostaszewski 
#36




Exercise for August 13, 2005
Please find it at:
http://www.math.ilstu.edu/krzysio/8...OExercise.pdf I hope you will enjoy it. Yours, Krzys' 
#37




Exercise for August 20, 2005
Please find it at:
http://www.math.ilstu.edu/krzysio/8...OExercise.pdf I hope you will enjoy it. Yours, Krzys' 
#38




August 27, 2005, Exercise
Please find it at:
http://www.math.ilstu.edu/krzysio/8...OExercise.pdf I hope you will enjoy it. Yours, Krzys' 
#39




September 3, 2005, exercise
Please find it at:
http://www.math.ilstu.edu/krzysio/935KOExercise.pdf I hope you will enjoy it. Yours, Krzys' 
#40




September 10, 2005, exercise
Please find it at:
http://www.math.ilstu.edu/krzysio/9...OExercise.pdf I hope you will enjoy it. Yours, Krzys' 
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examp, survival function 
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