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  #111  
Old 03-10-2008, 09:38 AM
sam_broverman sam_broverman is offline
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Default March 10, 2008 Exam P Question

The question can be found at
http://www.sambroverman.com/pqw/mar10-08p.pdf




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  #112  
Old 03-17-2008, 02:29 PM
sam_broverman sam_broverman is offline
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Default March 17, 2008 Exam P Question

The question can be found at
http://www.sambroverman.com/pqw/mar17-08p.pdf

(March 31, 2008) I have just posted a corrected solution to the problem.
Thanks to Allen Rogers for pointing out the error.



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Last edited by sam_broverman; 03-31-2008 at 09:35 PM..
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  #113  
Old 03-24-2008, 12:46 PM
sam_broverman sam_broverman is offline
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Default March 24, 2008 Exam P Question

The question can be found at
http://www.sambroverman.com/pqw/mar24-08p.pdf




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  #114  
Old 03-31-2008, 09:27 AM
sam_broverman sam_broverman is offline
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Default March 31, 2008 Exam P Question

The question can be found at
http://www.sambroverman.com/pqw/mar31-08p.pdf




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  #115  
Old 04-01-2008, 01:01 AM
michiko75 michiko75 is offline
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Quote:
Originally Posted by sam_broverman View Post
You can find the question at:
http://www.sambroverman.com/mar27p.pdf


Sam Broverman
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At the end of question(Mar 27/06), it said the average loss for all losses that are above 200 is 300. but why did you set up 300 = f(x|X>200) isn't it should be 300 = E(x|x>200)? please let me know. Thank you.
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  #116  
Old 04-01-2008, 10:28 AM
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Quote:
Originally Posted by michiko75 View Post
At the end of question(Mar 27/06), it said the average loss for all losses that are above 200 is 300. but why did you set up 300 = f(x|X>200) isn't it should be 300 = E(x|x>200)? please let me know. Thank you.
He didn't use 300 = f(x|X>200). He first gets a formula for f(x|X>200), notes that it is a Pareto distribution, then uses the equation of the mean for a Pareto distribution and sets that mean (and not the distribution itself) equal to 300.
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  #117  
Old 04-02-2008, 12:32 AM
michiko75 michiko75 is offline
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Thank you~
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  #118  
Old 04-03-2008, 01:05 AM
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Default Week of February 25/08

A loss random variable has a Poisson distribution with a mean of
An insurance policy on the loss has a policy limit of 1.
The expected insurance payment when a loss occurs is .8892 .
Find the expected insurance payment when a loss occurs for a policy on the same loss variable if
the policy limit is 2.
I saw the solution and seems this question is quite simple, BUT given one knows the meaning of "An insurance policy on the loss has a policy limit of 1"...

But how if i don't know the meaning? I never see this kind of description before
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  #119  
Old 04-03-2008, 08:23 AM
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Have you read the Risk and Insurance study note? If not, you should. The note uses the term "Benefit Limit" instead of "Policy Limit", so hopefully the exam would use "Benefit Limit".
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  #120  
Old 04-07-2008, 04:05 PM
sam_broverman sam_broverman is offline
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Default April 7, 2008 Exam P Question

The question can be found at
http://www.sambroverman.com/pqw/apr7-08p.pdf




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