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#141




Assuming you didn't know about it, though you probably should as it will certainly pop up in 4/C, here's a way to do a problem in an equivalent way.
Assuming you know that V(X) = E(V(XY)) + V(E(XY)) let's calculate the 2 pieces we are summing since we are just treating V(XY) as a R.V. and finding the expected value by multiplying outcomes by prob. of those outcomes You should know this simply because you should know that V(Blah) = E(Blah^2)  [E(Blah)]^2, well here Blah is E(XY). Now, and therefore and finally Last edited by Actuarialsuck; 07182008 at 10:57 AM.. 
#142




May 12/08 question
Could you remind me again what that shortcut is? I have not seen or heard of it i just know the variance of the bernoulli being pq?

#143




Quote:
Then You can derive this formula just by computing moments and knowing your algebra Spoiler: Last edited by Actuarialsuck; 07122008 at 09:19 PM.. 
#144




May 12/08 question
Thank you for the response. I wander how often that will show up for exam P? Im just starting the testing process so I havent seen any of the stuff beyond Exam P really. I think you meant to have a couple  signs in there instead of + but i got what you meant. Thanks again.

#145




Where?

#146




May 12/08 question
in the blah parts

#147




What do you mean? Point to actual places in the derivation.

#148




may 12/08 question
No you did the problem fine i think you made a typo when you had the v(blah)= E(blah^2) + instead of  (E(blah))^2

#149




Actuarialscuk,
Thanks for responding to the question. I was out of internet contact for a little while. Sam Broverman 
#150




I finally saw what you were talking when I realized I actually used the word "blah". Thanks, I corrected it.

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