

FlashChat  Actuarial Discussion  Preliminary Exams  CAS/SOA Exams  Cyberchat  Around the World  Suggestions 
Probability Old Exam P Forum 

Thread Tools  Search this Thread  Display Modes 
#51




hellz yeah.... i hope

#52




I got .003

#53




Quote:
uhoh...... I got .03 
#54




Regrettably, that means you've failed. That was the only nonpilot question.

#55




OK, it was the scenario when they were independent minus when they were mutually exclusive.
1P(fire union theft) 1(.1 +.3  .1*.3) = .63 in first case and 1(.1 +.3) = .6 .63.6 = .3 
#56




Or maybe .63.6 = .003 ...just maybe.

#57




Quote:
I also had that 4/3 thing in my exam...damn I spent so long trying to figure out how can I got something more than 1.... 
#58




It's OK if it's more than one. It's f(x) you are plugging it into...the greater than one thing would only be a problem if it was F(x). For example, f(x)=2x 0<x<1 is a common pdf. f(1)=2, but it's OK.

#59




Quote:
(i.e., what jexica said) 
#60




Quote:
f(x,y) = 4y/x. 0<y<x<1 Find Var(YX=2/3) I found the conditional distribution: fyx=2/3 = f(2/3,y)/fx(2/3) = 6y/fx(2/3) fx(x) = integral from 0 to x of 4y/x dy which i believe is 2x so, fx(2/3) = 4/3 < what went wrong there?? 
Thread Tools  Search this Thread 
Display Modes  

