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Old 05-02-2012, 02:50 PM
clive clive is offline
Join Date: Jan 2007
Posts: 67
Thumbs up SOA #85

To get EPV of benefit at time 2, SOA official solution integrates from 0 to infinity, see attachment, the integration result is 1000* e^0.08.

I am trying to integrate from 2 to infinity, with the formula below. I got 1000* e^-.04 as the result.

∫ (benefit) * (tPx) * (discount factor) * mu

∫ (1000e^.04t) * (e^-02t) * (e^-.04t) * (.02) dt

Apparently something is not correct in my formula, could you tell me how to fix it and your reasoning?

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Old 05-03-2012, 10:37 AM
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Practicing Practicing is offline
Join Date: Sep 2010
Location: NYC
Posts: 872

In your formula, when you integrate from 2 to infinity, you are doing it from the perspective of time t = 0. You need to do it from the perspective of time t = 2 because when calculating benefit reserves, we are conditioning on the fact that the life has survived to that time, in this case, t = 2.

Originally Posted by Abraham Weishaus View Post
I thought the actual exam was very similar to one of the last 2 ASM practice exams, but perhaps those underestimate the difficulty of the exam.
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Old 12-28-2017, 03:24 PM
jdman929 jdman929 is offline
Join Date: Aug 2017
College: University of Wisconsin - Madison
Posts: 4

I'm very lost on this problem... Why doesn't this work?

∫ (1000e^.04(t+2)) * (e^-02(t+2)) * (e^-.04(t+2) * (.02) dt from 2 to infinity.

Also in the official solution, what is going on with them breaking up mu(65+t) into mu(65)*t?

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