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  #61  
Old 10-28-2017, 04:10 PM
josephshack josephshack is offline
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Originally Posted by hach View Post
I did the same thing and found 1.6 which was b) . Why you think that you have done a mistake ? You didn't arrive to an answer ?
Hey Hach,

I was just having doubts and being a pessimist.

I guess I just wasn't sure if I used p_{[58]+2} or p_{60}

in the expression for e_{60}, to solve for e_{61}.. but I know I should have used p_{60}. Now that I think back to moments where I glanced at my scantron, I think I did have B for that question.
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  #62  
Old 10-28-2017, 05:03 PM
cixelsidmaikool cixelsidmaikool is offline
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ha.. I didn't actually use v on the exam, but I spaced here when I was writing the formula.

but yeah no v. for e60, it would be e60 = p60 * (1+e61), not p[60] (or any select probability for that matter), because e60 is indicating that the member would have been selected at sometime age 57 or earlier
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  #63  
Old 10-28-2017, 05:29 PM
josephshack josephshack is offline
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Originally Posted by cixelsidmaikool View Post
ha.. I didn't actually use v on the exam, but I spaced here when I was writing the formula.

but yeah no v. for e60, it would be e60 = p60 * (1+e61), not p[60] (or any select probability for that matter), because e60 is indicating that the member would have been selected at sometime age 57 or earlier
Word, I agree with you.

I am using the {} to denote subscripts. So, p_{60} in my language is really just p60.

I think we are on the same page!
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  #64  
Old 10-28-2017, 05:30 PM
mel.fel mel.fel is offline
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How did you get the premium? It was like
1030= P*(continuous ten year annuity state 0 (a00) + .75* continuous ten year annuity state 1 (a01))

I calculated a00 as 1/(.06+.025)*(1-e^-.085*10) and a01 as integral from 0 to 10 of e^-.06*tpx01 that was from the first question and I kept getting 95 or something like that which wasn't right
that's what i did as well. maybe it was a calculation error?
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  #65  
Old 10-28-2017, 05:38 PM
josephshack josephshack is offline
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Does anyone remember what number the 95th percentile question was on the multiple choice?
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  #66  
Old 10-28-2017, 06:02 PM
hunkal hunkal is offline
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that's what i did as well. maybe it was a calculation error?
Aw man. Hopefully I will get some partial credit. I was getting so frustrated when I couldn't figure out what I was doing wrong
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  #67  
Old 10-28-2017, 06:02 PM
hunkal hunkal is offline
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Does anyone remember what number the 95th percentile question was on the multiple choice?

Do you remember anymore details about the question? I can really remember it. Was it ILT and discrete?
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  #68  
Old 10-28-2017, 07:04 PM
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DarchArvor DarchArvor is offline
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Originally Posted by josephshack View Post
Does anyone remember what number the 95th percentile question was on the multiple choice?
same question, I think it was 13 or 11.
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  #69  
Old 10-29-2017, 10:28 AM
cpolek1 cpolek1 is offline
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Does anyone remember what number the 95th percentile question was on the multiple choice?
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same question, I think it was 13 or 11.
I think it was 11.

11 was the one I guessed on - I was getting answers in the 40000's and all the choices were in the 60000's.
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Old 10-29-2017, 10:35 AM
cpolek1 cpolek1 is offline
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I thought for these types of problems you went with the method that yielded the higher cost of insurance which for this question I determined it to be without corridor factor, which is it might seem just as many chose FA-AV as those who did AV*(corridor-1).

Of course this was one of last few concepts I started understanding better in the last month so maybe my calculations could have been off.
For these questions you calculate AV_6 without accounting for the corridor factor (CF). Then if CF*AV_6 < Total DB, you replace DB with CF*AV_6 in the formula for COI and recalculate AV_6.

Since COI = (DB-AV_6)vq, you get COI = (CF*AV_6-AV_6)vq = AV_6(CF-1)vq

And then AV_6 = (AV_5 + P - e)(1+i) - AV_6(CF-1)vq(1+i)
for this problem, credited and mortality interest were the same, so:
AV_6 = [(AV_5 + P - e)(1+i)] - AV_6(CF-1)q
AV_6 + AV_6(CF-1)q = [(AV_5 + P - e)(1+i)]
AV_6 [1+ (CF-1)q] = [(AV_5 + P - e)(1+i)]
AV_6 = [(AV_5 + P - e)(1+i)] / [1+ (CF-1)q]
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