Actuarial Outpost Not Understanding This Derivation
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 Long-Term Actuarial Math Old Exam MLC Forum

#1
01-13-2019, 01:07 PM
 SweepingRocks Member SOA Join Date: Jun 2017 College: Bentley University Posts: 59
Not Understanding This Derivation

I know this might be going back a few years in math lessons, but please bear with me.

https://imgur.com/jA97vSz <-- Here's the derivation I'm having issues with

So I understand the principles of why I'm supposed to be doing these steps, but the issue for me is going from that second line to the third line. This is the chain rule, I know, but when taking the derivative of the portion in the exponent, would the results not be -B/ln(c) (c^x) (c^t -1) (ln(c)) or -B/ln(c) (c^x) (c^t) (ln(c)) + B/ln(c) (c^x) ln(c) ?

When they derive it in the problem, it seems they are changing the ct - 1 from the second line to ct and I'm not seeing why. Perhaps if someone could do that part out or explain it, I'd get a better understanding.
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FM P MFE STAM LTAM in April

Former Disney World Cast Member, currently no idea what I'm doing
#2
01-13-2019, 01:12 PM
 SweepingRocks Member SOA Join Date: Jun 2017 College: Bentley University Posts: 59

It's because we're taking the derivative of t, not the derivative of x. How come I always figure these out right after I post them? :P
__________________
FM P MFE STAM LTAM in April

Former Disney World Cast Member, currently no idea what I'm doing
#3
01-13-2019, 01:12 PM
 Transitive Tangerine Member COPA Join Date: Oct 2018 Studying for PA Posts: 494

you're differentiating with respect to t, so treat everything else like a giant constant, so rewrite the exponent as: K(c^t - 1)

= Kc^t - K

If you take the derivative of that, you just get:
K(c^t)(lnc) - 0
= K(c^t)(lnc)
#4
01-13-2019, 01:13 PM
 Transitive Tangerine Member COPA Join Date: Oct 2018 Studying for PA Posts: 494

Quote:
 Originally Posted by SweepingRocks It's because we're taking the derivative of t, not the derivative of x. How come I always figure these out right after I post them? :P
xD