

FlashChat  Actuarial Discussion  Preliminary Exams  CAS/SOA Exams  Cyberchat  Around the World  Suggestions 

ShortTerm Actuarial Math Old Exam C Forum 

Thread Tools  Search this Thread  Display Modes 
#1




SOA #65
Hello!
A quick question about NonPoisson frequency and classical credibility: For this question I tried to use the following formula from the ASM manual table: 42.1 n0 * ((Var(n)/E[N]) + (Var(s)/(E[x]^2)) Where N represents frequency and x represents severity. However the SOA solution uses another formula to get the full credibility value: n0 * (Var(S)) Where: Var(s) = E[N] * Var(x) + Var(N) * (E[x])^2 Can someone explain why the second formula be used and not the first to calculate the full credibility value? Is there something in the wording of the problem? Thank you for your help!
__________________
EXAMS: VEE: FAP: 
#2




This is the danger in memorizing a bunch of different formulas for the full credibility standard for different casesyou get confused about which to use where.
For full credibility for a random variable W, the minimum number of _observations_ of W for full credibility is (y / k)^2 Var[W] / E[W]^2. In #65, my W is aggregate severity (denoted by X in the problem), and you have 2500 observations of the value of aggregate severity. The formula you were applying inappropriately is for the minimum (expected) number of claims for full credibility for aggregate severity rather than for the minimum number of observations of aggregate severity.
__________________
Jim Daniel Jim Daniel's Actuarial Seminars www.actuarialseminars.com jimdaniel@actuarialseminars.com 
#3




Thank you for the reply!
Yes, that is a subtlety that was lost on me. I was thinking about the 2500  not as observations but as exposures... I think I need to study this further as I'm not sure I fully understand it yet. Thank you again!
__________________
EXAMS: VEE: FAP: 
#4




That basic formula always gives you the minimum number of observations of W. You just have to ask yourself “when do I observe a value of W?” When W is frequency or aggregate severity per exposure unit, the answer is “every time an exposure unit goes by”. When W is severity per accident, the answer is “every time an accident occurs”.
__________________
Jim Daniel Jim Daniel's Actuarial Seminars www.actuarialseminars.com jimdaniel@actuarialseminars.com 
Thread Tools  Search this Thread 
Display Modes  

