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#1




Joint pdf of random variables! Help!
Hello,
So, I understand that in order to get the probability of Y, you will kind of need to break it down into three probabilities. 1) P[0 <= X <= 0.5] = F(0.5)  F(0) = 1/20 2) P[9.5 <= X <= 10] = F[10]  F[9.5] = 1/20 And, these two are correct. However, I am having trouble finding out the probability of the remaining numbers, such as, 1,2,3,4,5,6,7,8 and 9...I believe that it is 9/20. However, the actual answer is 1/20. And I can't really figure out how. Thank you for all the help! 
#3




Don't forget P(Y = 0).
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#4




Oh...I see what you mean...thank you so much for your help!

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