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#51
02-24-2007, 02:34 PM
 gosuruss Member SOA Join Date: Feb 2007 Favorite beer: whatever is free Posts: 4,317 Blog Entries: 2

does anyone know what the term

"net of deductible" means?
#52
02-24-2007, 02:37 PM
 Gandalf Site Supporter Site Supporter SOA Join Date: Nov 2001 Location: Middle Earth Posts: 26,458

If the loss is 15, and there is a deductible of 3, you will receive 12, the loss net of (i.e., less) the deductible.
#53
02-24-2007, 02:46 PM
 gosuruss Member SOA Join Date: Feb 2007 Favorite beer: whatever is free Posts: 4,317 Blog Entries: 2

Quote:
 Originally Posted by Gandalf If the loss is 15, and there is a deductible of 3, you will receive 12, the loss net of (i.e., less) the deductible.
gabage
#54
02-24-2007, 02:49 PM
 gosuruss Member SOA Join Date: Feb 2007 Favorite beer: whatever is free Posts: 4,317 Blog Entries: 2

my friend got a problem where it was

you roll a die until you get three sixes, calculate variance of x (amount of times you roll)

took us a while to figure it out at home but it is just negative binomial, rq/(p^2)

3(5/6)/(1/6)^2
#55
02-24-2007, 02:53 PM
 Generalshamu Member SOA Join Date: Oct 2006 Location: LA Favorite beer: Heineken Posts: 811

Quote:
 Originally Posted by jy006m Generalshamu, do you remember a joint probability function? ...and they asked you to calculate E(Y) given X=1/4 or something? One question I remember was something like: A man and woman arrive separately to some place between 3pm and 4pm, where it follows a uniform distribution. What is the probability that one will have to wait for the other for more than 20 minutes? Damn, for some reason I blanked out and didn't know what to do. I tried to set it up as a combination of normal rvs to calculate |X-Y|>20. I just now realize as I'm recalling this question that this was a joint density function where f(x,y)=1/3600 and |X-Y|>20. This should've been really easy!! the answer choices were A. (don't remember) B. 2/9 C. 1/3 D. 4/9 E. 2/3 I had it narrowed down to C and D and guessed C. But now I think the correct answer was 4/9. @#*&(*#@%!
No I did not get this one sorry...I got one where it had to deal with a husband and wife's expected lifetimes/probability of their deaths...
#56
02-24-2007, 02:55 PM
 Generalshamu Member SOA Join Date: Oct 2006 Location: LA Favorite beer: Heineken Posts: 811

Quote:
 Originally Posted by jy006m Yeah, after I calculated it and got 0 I was skeptical because it was such a nice round number, so I drew a graph of it to try to convince myself.
So wait is the question I had equal to 0 or 2/9???

Because I remember there being a question that read, find E(X^4 * Y) I just can't remember if this was for the question with f(x,y) = 2|x|y....???
#57
02-24-2007, 03:10 PM
 jy006m Member SOA Join Date: Aug 2006 Studying for FAP Posts: 924

Oh, they were different questions??? crap. I definitely remember that density function as well as the E(X^4Y) and putting down 0 for something.

Hmm, after thinking about it, it must've been. I remember separating the integrals out based on x being positive or negative and having to multiply x^4y into each integral.

Of course, I could be completely wrong. The exam is quickly becoming a blur.

So E(X)=2/9 and E(X^4*Y)=0?

Last edited by jy006m; 02-24-2007 at 03:15 PM..
#58
02-24-2007, 03:13 PM
 Generalshamu Member SOA Join Date: Oct 2006 Location: LA Favorite beer: Heineken Posts: 811

Quote:
 Originally Posted by jy006m Oh, they were different questions??? crap. I definitely remember that density function as well as the E(X^4Y) and putting down 0 for something. Hmm, after thinking about it, it must've been. I remember separating the integrals out based on x being positive or negative and having to multiply x^4y into each integral.
Well then that was it! I'll redo the problem to make sure this was it...
#59
02-24-2007, 03:18 PM
 fengxinzi Member Join Date: Feb 2006 Posts: 40

i think there r different questions....how come i didnt get/or rmb some of the questions u guys posted? -_-"
#60
02-24-2007, 03:19 PM
 jy006m Member SOA Join Date: Aug 2006 Studying for FAP Posts: 924

I am really confused now. I reread the old posts, which say E(X)=0 and E(X^4*Y)=2/9. God.

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