Grasp Question 39, Question 40 Errata and misc

[Julietn528]

Question 39:

Should read:

Male: (.05*.75)+(.25*.86) + .30*1.08 +.05 *1.39

The female should also have a plus sign instead of a multiply sign between the third and fourth terms.

I am also getting a different answer for the multiplicative factors; I am getting,

.646 and .373 for the average age factors instead of .9938 and 1.0657

is that correct? Or am I making an error?

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Question 40:

For B you solve the male capitation rate for a male under 40 which is 16.47;

when this is carried to the next page to calculate the male capitation rate the number that is used is 16.64; but this should still be 16.47, correct?

[MarsLasar]

Originally Posted by Julietn528

Question 39:

Should read:

Male: (.05*.75)+(.25*.86) + .30*1.08 +.05 *1.39

The female should also have a plus sign instead of a multiply sign between the third and fourth terms.

I am also getting a different answer for the multiplicative factors; I am getting,

.646 and .373 for the average age factors instead of .9938 and 1.0657

is that correct? Or am I making an error?

----------------------------------------------------------------

Question 40:

For B you solve the male capitation rate for a male under 40 which is 16.47;

when this is carried to the next page to calculate the male capitation rate the number that is used is 16.64; but this should still be 16.47, correct?

39) You need to divide 0.646 by (0.05+0.25+0.3+0.05) and then you will get the correct value of 0.9938.

40) 16.47 is not correct. 16.64 is the right number.

[Julietn528]

I'm confused, can you right out the full equation for 39 and 40 to get to .9938 and to get to 16.64?

[MarsLasar]

Old Age Factors for Old Product (Male) = [.05*.75+.25*.86+.3*1.08+.05*1.39]/[.05+.25+.3+.05] = 0.9938

15.80 = X*[.2+.1*1.2/1.01+.2*1.15/1.01+.1*1.27/1.01+.4*.7/1.01]
=> X = 16.64

[Julietn528]

Originally Posted by MarsLasar

Old Age Factors for Old Product (Male) = [.05*.75+.25*.86+.3*1.08+.05*1.39]/[.05+.25+.3+.05] = 0.9938

15.80 = X*[.2+.1*1.2/1.01+.2*1.15/1.01+.1*1.27/1.01+.4*.7/1.01]
=> X = 16.64

Okay I see, so there were some typos; thanks for clarifying.