Spring 2011 Discussion

[peem]

Originally Posted by Wolf Follower

The Markov chain one where we had to find P, did everyone interpret that as receiving the last payment at time 4, making the incoming and outgoing offset by 1?

WF

I didn't count the last premium payment but I could see who that could be the correct interpretation.

[Wolf Follower]

Did you guys remember to divide by the probability of reaching the starting age on the first one?

WF

[aspen_ashes]

Yeah, below the 95% test statistic on the two-dimensional chi-squared.

[MrTomD]

Originally Posted by Is This Wilt Chamberlain?

Yeah that was nice of them. I still spent a minute staring at it saying "I have to be missing something..."

Haha I did the same thing!

[peem]

Originally Posted by MrTomD

I believe there was a simple formula to find the other P when given the other two P's and the reserve. (Thanks MLC)

What was it? I recall going over it but was one of those things I didn't bother to memorize. However, this question was the 2nd of my guesses because I came up with a reasonable answer.

[Wolf Follower]

Originally Posted by aspen_ashes

Yeah, below the 95% test statistic on the two-dimensional chi-squared.

Same here.

WF

[peem]

Originally Posted by Wolf Follower

Did you guys remember to divide by the probability of reaching the starting age on the first one?

WF

Do you mean the 2nd one? S(x + t)/S(x)

[ephy26]

Originally Posted by peem

Do you mean the 2nd one? S(x + t)/S(x)

How did you solve that problem?

[Wolf Follower]

Originally Posted by peem

Do you mean the 2nd one? S(x + t)/S(x)

I thought that was the first one.

WF

[aspen_ashes]

First one was the easy variance of future lifetime of constant mortality.