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#1
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Not sure why I keep getting this wrong.
Solutions set up the integral from t/2->2 and 3->4 I set it up from 3->2x and 1.5->2 As far as I can tell the two are equivalent. Other than that I did all the same things, so the only other possible mistake I could imagine would be in the algebra, which would make me feel dumb after triple checking. So why doesn't this work |
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#3
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Math on a computer always feels strange
int(1.5->2 int 3->2x(3x/8dt)dx) = int(1.5->2 3xy/8(3->2x)dx) = int(1.5->2 3x^2/4-9x/8 dx) = x^3/4-9x^2/16 (1.5->2) = 2-2.25-.84375+1.265625 = .171875 Completely perplexed as to how multiple times of doing this (including right before typing this) gave me the wrong answer. lol me |
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#4
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math on a computer is easier to read if you use tex http://www.actuarialoutpost.com/actu...93#post1409493 |
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