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#1
03-14-2012, 02:36 PM
 georgestouma Member CAS SOA Join Date: Mar 2012 Studying for C College: Postgraduate Posts: 407
"asm mlc 11th edition exam2 nb 19 page 1151"

in the 6th line , the (59/60)(20/29)(1/1.03^10) ,, i think that the 20 must be 19 =100-71-10 ,,, otherwise how the 20 is calculated?
#2
03-14-2012, 05:52 PM
 Abraham Weishaus Member SOA AAA Join Date: Oct 2001 Posts: 6,194

I'm calculating $A_{70:\overline{10|}}$, not $A_{71:\overline{10|}}$.
#3
03-15-2012, 03:06 AM
 georgestouma Member CAS SOA Join Date: Mar 2012 Studying for C College: Postgraduate Posts: 407

we are finding a pure endowment ! it is nPx*V^n ,,,,,, 59/60 for age 70 , so (n-1)P(x+1)=9P71=(100-71-9)/(100-71)=20/29. So this is it ,, thank you very much for your help in all my posts , and i will post more !!

Last edited by georgestouma; 03-15-2012 at 08:20 AM..

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