"asm mlc 11th edition exam2 nb 19 page 1151"

[georgestouma]

in the 6th line , the (59/60)(20/29)(1/1.03^10) ,, i think that the 20 must be 19 =100-71-10 ,,, otherwise how the 20 is calculated?

[Abraham Weishaus]

I'm calculating , not .

[georgestouma]

we are finding a pure endowment ! it is nPx*V^n ,,,,,, 59/60 for age 70 , so (n-1)P(x+1)=9P71=(100-71-9)/(100-71)=20/29. So this is it ,, thank you very much for your help in all my posts , and i will post more !!