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  #1  
Old 07-27-2012, 10:53 AM
samzhang2003 samzhang2003 is offline
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Join Date: Jun 2012
Location: New Jersey
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Default TIA practice exam 4, Q.9

An insurance company categorizes its customers as low risk, medium risk, and high risk. Suppose that
20% are low risk, 50% are medium risk, and 30% are high risk. If 5 customers are chosen at random,
what is the probability that exactly twice as many of them are low risk as high risk given that at least
one customer chosen is high risk?

I'm having trouble to understand the highlight sentence.
Does it mean 2L= H or 2H=L?

Originally I thought it's 2L=H, then I saw "twice as many girls as boys" means 2B=G. So I'm confused now.

Thanks
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  #2  
Old 07-27-2012, 11:48 AM
KDB10 KDB10 is offline
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If 5 are high risk, and twice as many are low risk as high risk, then ten (2*5) are low risk.

Therefore, 2H = L (or substituting numbers, 2*5 = 10)

Same with your girls & boys deal. If there is one boy, and there are twice as many girls as boys, there are 2*1 = 2 girls, or 2B = G
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  #3  
Old 07-27-2012, 04:27 PM
ronaldy27's Avatar
ronaldy27 ronaldy27 is offline
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Join Date: Jan 2012
Location: 9th dimension
Studying for C and MLC
College: SUNY Binghamton Alumni
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Default

Quote:
Originally Posted by samzhang2003 View Post
An insurance company categorizes its customers as low risk, medium risk, and high risk. Suppose that
20% are low risk, 50% are medium risk, and 30% are high risk. If 5 customers are chosen at random,
what is the probability that exactly twice as many of them are low risk as high risk given that at least
one customer chosen is high risk?

I'm having trouble to understand the highlight sentence.
Does it mean 2L= H or 2H=L?

Originally I thought it's 2L=H, then I saw "twice as many girls as boys" means 2B=G. So I'm confused now.

Thanks
Remember, you are trying to set them equal.
So if you look at the statement, "exactly twice as many of them are low risk as high risk," then to make them equal you have to have 2(H)=(L)
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  #4  
Old 07-29-2012, 01:23 PM
samzhang2003 samzhang2003 is offline
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Join Date: Jun 2012
Location: New Jersey
Studying for Exam C
College: University of Rochester
Posts: 9
Default

Thanks for the explanation.
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