Exam P Help Please

[Dansanon]

By definition ( "/" inside () means conditional )
P(A/B)= P(A∩B) / P(B)..WHY ISN'T P( (AUB) / C) = P( (AUB) ∩ C) / P(C).

ALSO WHAT IS P( C/ (AUB) )=?..PLEASE PROVIDE CLEAR PROOF. THANKS.

[crusher2011]

you are exactly right about P(AUB|C)=P((AUB)∩C)/P(C), but it can be simplified if A, B, and C are independent, you can do that as an exercise if you want. if you want the answer reply to this.

P(C|AUB)=P((AUB)∩C)/P(AUB)=P((A∩C)U(B∩C))/P(AUB)=(P(A∩C)+P(B∩C)-P(A∩B∩C))/(P(A)+P(B)-P(A∩B)) which is complete unless A B and C are independent. remember if A and B are independent, then P(A∩B)=P(A)P(B)

[Dansanon]

so many people view this post but no answer can somebody throw some ideas please?

[trainump]

Originally Posted by Dansanon

so many people view this post but no answer can somebody throw some ideas please?

What's wrong with what crusher said?

[Michaluk]

Originally Posted by Dansanon

By definition ( "/" inside () means conditional )
P(A/B)= P(A∩B) / P(B)..WHY ISN'T P( (AUB) / C) = P( (AUB) ∩ C) / P(C).

It is. That's your answer.

[crusher2011]

P(AUB|C)=P(AUB) if A, B, and C are independent events. Any other answers must have some other type of defined relationship.

[Actuarialsuck]

Originally Posted by crusher2011

P(AUB|C)=P(AUB) if A, B, and C are independent events. Any other answers must have some other type of defined relationship.

Are you sure all of them need to be ind.?

[Actuarialsuck]

Originally Posted by fargo_viper

http://www.actuarialoutpost.com/actu...d.php?t=244660

That's why I love when people start multiple threads with the same problem. :facepalm: