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#1
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Problem:
"Melanie wants to buy an annuity of 15 years providing 30 semi-annual payments, the first payment being six months after the purchase of the annuity. During a year, the semi-annual payments are the same amounts. After the first year, at the beginning of each year, the payment level are decreased by 4%. If the semi-annual interest rate is i(2) = 10%, capitalized two times a year, how much should cost the annuity ?" My attempt solving this problem: Year 1: R*(a(2]i)*v^0 Year 2: (96/100)R*(a(2]i)*v^2 Year 3: (92/100)R*(a(2]i)*v^4 ... Year 15: (28/100)R*(a(2]i)*v^28 => PV = R*(a(2]i)*v^0 + (96/100)R*(a(2]i)*v^2 + ... + (28/100)R (a(2]i)*v^28 => PV = R*(a(2]i)* Sigma (from k=0 to k=14) of {(1 -4%*k)*[v^(2k)]} -------------------------------------------------------------- I got stuck it the geometric series ... Is my understanding about this question correct T____T Sorry for taking your time reading this question (i) And thanks for your concerning (ii) ( not sure if (i) and (ii) are similar ?) Sincerely, |
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#2
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i not quite understand what u did but it quite long and you won't have that much time in exam condition so you need something short here is what i do
do you know the geometric formula for varying annuity? if not better download a forumla sheet from here where people post their formula sheets: http://www.actuarialoutpost.com/actu...ad.php?t=92252 the one i will using is this one 1st you need put first two payment into 1 because the annuity increase every two payment so P*S_(2)_0.05 then annual effective rate: 1.05^2-1=0.1025 then plug in equation P*S_(2)_0.05*{[1-(0.96/1.1025)^15]/(0.1025+0.04)}= P*2.05*6.1374=12.5816P well since it didn't give P, i think this is the answer because we pretty much have no clue how much money is involved. unless answer is something else let me know. |
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#3
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Thanks for your concerning ( it is likely that you are the only one here helping me to solve my questions in detail T___T )
let's X = P*S_2_0.05 = 2.1025P For the end of 1st year ( 2 times ) : X= 40%X + 15*4%X i=(1+i(2)/2)^2 -1 = 0.1025 For the end of 2dn year (4 times): 96%*X=40%X + 14*4%X ... For the end of 15th year (30 times):44%*X== 40%X +4%X a_(15)_0.1025=a_n_i=7.49876 (Da)_n_i = (n - a_n_i)/i= PV = 40%X*a_n_i + 4%X*(Da)_n_i = X*2.9995 + 7.297X = 21.6484P Oh ! It's 4% decrease in payment level each yar, I got it wrong. Thought it is decrease 4% R each year >___< Sorry ! Your solution is right. About the amount of P is a little bit ambiguous for me too ><. Because in problem 2, I have to face with a ambiguous payment too. Problem 2: About Perpetuity. The following questions are related. (a) Consider an annuity with payments of 1/m made each month. The nominal interest rate compounded each month is i(12) = 4%. Use the geometric series to express the present value of this annuity in terms of a_n_i and i. (b) Using the previous assumptions, consider a perpetuity of 1/m, that is an infinite series of payments of 1/m. Express the present value of the perpetuity of 1/m in terms of i(12). (c) Consider the perpetuity in (b). Express the present value of the perpetuity in terms of i (12). I have already emailed her, asking about that question ( My attempt is like : a) PV = 1/m * 1/(1+i(12)/12) * [(1-v^n)]/([i(12)/12]/{1+[i(12)/12]}) note: all i(12)/12 is replaced by (1+i)^-12 -1 but she says this will not consist 1/m (which means I have to change 1/m to an equation respects to a_n_i and i ) but I just don't know how ? Last edited by eragonngo; 09-28-2012 at 12:22 AM.. |
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#4
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Quote:
if u have trouble see it draw a time diagram it will help you out should be like payment__R____R__0.96R___0.96R____0.92R .... ----------|-----|-----|-------|---------| time_____0.5___1___1.5_____2_______2.5 .... if u want use R*a_2_i instead of R*s_2_i is fine too just the 2nd part you will use the geometric annuity due instead of immediate it will be like R* a_2_i * a(dot)_15_[(0.1025+0.04)/0.96]=12.5816R Quote:
part b i am not quite get what is 1=m thing? so 1/m become 1/1? then it will be 1/(0.04/12)=300 so is c not quite get what is it asking....otherwise it is just same answer as b. if she ever give u the answers please let me know i am kind curious Last edited by liujeffqi; 09-25-2012 at 01:39 AM.. |
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#5
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Hmmm, I still don't get the term: " at the beginning of each year, the payment level are decreased by 4%" . So it's 100*(1-4%) in year 2(payment 3). But at the beginning of year 3 (payment 5): Will it be 100*((1-4%)^2) of Geometric frequency or 100*(1-2*4%) of Arithmetic frequency T___T ?
Now she adds more data in question 2) where m = 12 => PV = (1/12)*a_(n/12)_(i(12)/12) . And I will represent it in term of a_n_i and i ... Hope it will be good .. But at the case b) and c) while she states they are the same. Still can't get it. Can you enlighten little me this time, master T____T The solution will be post on Friday 28/09/2012 (UTC -5.00) ... hope I will survive |
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#6
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oh my mistake ya it is 100*((1-4%)^2) of Geometric frequency forget to change it sorry about that.
well it your sure it is PV = (1/12)*a_(n/12)_(i(12)/12) not PV = (1/12)*a_(12n)_(i(12)/12)? but anyway since it is Perpetuity n should be inf. so it should still ends up like what i have (1/m)a_inf =(1/m)(1/i) just become (1/12)a_inf =(1/12)(1/i) and i still don't get what is 1=m thing so if it is just asking to plug in m=1 then answer will 300.. and c i don't see anything new same function same plug in so answer is 300 also if what i guessing is right. but i don't know when the soultion is posted do you care to post it out so i can get what she is really asking? if u don't want post it out message is fine too Thanks |
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#7
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Aw my mistake, it's 1/m in question b). So it's like a_inf = (1/m)*(1/i). But question a) isn't about Perpetuity, isn't it ?
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#8
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Got question a) like: (1/12)*a_n_i* (i / ((1+i)^(-12) -1)) ... Damm this week 's assigment is pure Math .. not even actuarial science and finance in this case =)) I will post the solution and assignment tomorrow :P
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