![]() |
|
|
#1
|
||||
|
||||
|
T(x) and T(y) are independent. you are also given the following info:
k q_x+k q_y+k 0 .08 .1 1 .09 .15 2 .1 .2 Determine the probability that the curtate future lifetime of (xy_last surv) equals 1 a) Less than .03 b) .03 - .0305 c) .0305 - .031 d) .031 - .0315 e) at least .0315 I think my formula is incorrect for last survivor curtate functions... |
|
#2
|
||||
|
||||
|
Do you know what the answer is?
|
|
#3
|
||||
|
||||
|
B
|
|
#4
|
||||
|
||||
|
Quote:
|
|
#5
|
||||
|
||||
|
The answer is 0.030258. Sox, I don't know what formula you have but think logically: The Prob (of x to die in 1 and y die in 0) + Prob (of y to die in 1 and x in 0) + Prob (of both die in time 1).
__________________
Everyone deserves a bit of luck! |
|
#6
|
||||
|
||||
|
JJ beat me to it!
|
|
#7
|
||||
|
||||
|
thanks - I was using the formula for JSS -forgetting that it was not the formula for LSS and was so stuck on why it wasn't working that I didn't think it through. I guess that's a lesson in not blindly trying to apply formulas!
Thanks for the help all |
|
#8
|
||||
|
||||
|
Quote:
__________________
Everyone deserves a bit of luck! |
|
#9
|
||||
|
||||
|
Quote:
|
|
#10
|
||||
|
||||
|
Quote:
__________________
Everyone deserves a bit of luck! |
![]() |
| Thread Tools | |
| Display Modes | |
|
|