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  #21  
Old 09-16-2005, 07:34 AM
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Maybe it is .2. I certainly see why you would think that. Here is my thinking (not sure what it is worth):

abar_x = int from .1 to .3 of (mu + .1)^-1/.2dmu = 5ln(2)
Premium = [1 - .5ln(2)](5ln2)
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  #22  
Old 09-16-2005, 10:11 AM
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Oooh, no you must be right. It's like a mixed distribution from loss models. Nice!
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  #23  
Old 09-21-2005, 11:13 AM
G.V.Ramanathan G.V.Ramanathan is offline
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Default #3 and solutions to past problems
on www.actuarialexamprep.us
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  #24  
Old 09-21-2005, 12:02 PM
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.6
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  #25  
Old 09-23-2005, 10:57 AM
G.V.Ramanathan G.V.Ramanathan is offline
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I am afraid .6 is not the correct answer.
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Last edited by G.V.Ramanathan; 09-23-2005 at 11:01 AM..
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  #26  
Old 09-23-2005, 02:24 PM
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I think there should be a limit to the number of attempts, but was does my opinion matter? Now I'm going with .5.
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  #27  
Old 09-26-2005, 02:20 PM
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I also got 0.5
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  #28  
Old 09-28-2005, 08:47 AM
G.V.Ramanathan G.V.Ramanathan is offline
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Default #4
is on www.actuarialexamprep.us
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  #29  
Old 09-28-2005, 01:43 PM
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.857 for # 4?
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  #30  
Old 09-30-2005, 10:04 AM
G.V.Ramanathan G.V.Ramanathan is offline
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I don't think so.
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