![]() |
|
|
|||||||
| FlashChat | Actuarial Discussion | Preliminary Exams | CAS/SOA Exams | Cyberchat | Around the World | Suggestions |
Life Actuarial Jobs | Salary Surveys | DW Simpson & Co. | Casualty Jobs |
![]() |
|
|
Thread Tools | Display Modes |
|
#1
|
||||
|
||||
|
Why when the cap is placed at 3, do we use the Demand equation to determine amount produced? Since when is a monopolist producing at the demand as long as there is no optimal two-part tarriff? What changes from using the MR curve to the Q<sub>D</sub> curve?
--Avi ![]()
__________________
All scientists defer only to physicists Physicists defer only to mathematicians Mathematicians defer only to G-d! --with apologies to Dr. Leon Lederman |
|
#2
|
||||
|
||||
|
I can't answer in the terms you're using, but here's what's happening.
Monopolist wants to maximize its profit = Revenue - Costs = (8y - 4y^2) - (.5+2y) = 6y-4y^2-.5 Without constraints, you can get the maximum by setting dProfit / dy = 0; that's the same as saying Marginal Revenue = Marginal Cost. With constraints, Revenue = 3y for y <= 1.25 (the most you can charge is 3, and you will sell them all; people would be willing to pay more than 3). Profit = 3y - (.5 + 2y) = y - .5, for y < 1.25. That's an increasing function of y, produce as many as you can up to the 1.25 point where the Profit function is different. At 1.25, profit function reverts to 6y - 4y^2 -.5. Derivative would be negative; don't produce any more. I don't think you could do all that within exam time constraints, but maybe it will help you understand the study material. |
|
#3
|
||||
|
||||
|
Thank you, the theoretical underpinnings always help to elucidate the material
--Avi
__________________
All scientists defer only to physicists Physicists defer only to mathematicians Mathematicians defer only to G-d! --with apologies to Dr. Leon Lederman |
![]() |
| Thread Tools | |
| Display Modes | |
|
|